它是安全的强制转换为int为void指针和回再次诠释？ [英] Is it safe to cast an int to void pointer and back to int again?

问题描述

在C和/或C ++：？是安全投int类型为void指针和回再次诠释

In C and/or C++: is it safe to cast an int to void pointer and back to int again?

href=\"http://stackoverflow.com/questions/3567905/c-is-it-safe-to-cast-pointer-to-int-and-later-back-to-pointer-again\">C++:它是安全投指针为int，后来回再次指针？。

Based on the question "C++: Is it safe to cast pointer to int and later back to pointer again?".

推荐答案

在大多数现代司空见惯的机器，大概。

In most modern-day commonplace machines, probably.

不过，我敢打赌，有一些模糊的编译器或配置（例如，一个16位寻址，使用32位的整数运算计算机）不是这样的。

However, I'd bet that there is some obscure compiler or configuration (say, a 16-bit addressed machine that uses 32-bit integer arithmetic) where that is not the case.

一个 uintptr_t形式保证同时容纳，不过，如果你想这样使用该类型。

A uintptr_t is guaranteed to hold both, though, so use that type if you want to.

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