malloc调用崩溃，但在其他地方工作 [英] Malloc call crashing, but works elsewhere

问题描述

我不知道是否有人可能会对此有什么见解...

I wonder if anyone might have any insight on this...

我的程序崩溃对此调用：

My program is crashing on this call:

void subtract(data* array,data* inverse,int a, int b, int q, int n)
{

data* arraytomultiply;
arraytomultiply = (data *)malloc(sizeof(data*) * n);

如果数据只是持有一个int（这是为了方便切换类型时，更新版本）

Where data just holds an int (it's for convenience when switching types later)

typedef struct { 
        int value;
}data;

我试过很多乱搞这里改变指针作为我不是对他们有信心可言，但无济于事。

I've tried lots of messing around with changing the pointers here as I'm not confident on them at all, but to no avail.

但奇怪的是，该计划早得多同样的通话效果，我值分配给它，并可以打印出来，一切都..：

The strange thing is, much earlier in the program this same call works, I assign values to it and can print them out and everything..:

data* array;
array = (data*)malloc(sizeof(data*) * m * n); // m * n entries

这可能是使用的（虽然我不知道为什么），有一件事是，当早期的作品是一个void函数中的，而当它崩溃它在一个从算法中调用的函数。但我看不出这可能会影响它在所有，因为我尝试不使用任何的参数做等...

One thing that might be of use (though I have no idea why) is that when it works earlier it's during a void function, whereas when it crashes it's in a function called from within an algorithm. but I don't see how this could affect it at all, given what I'm trying to do isn't using any of the arguments etc...

任何想法？

推荐答案

难道不应该的sizeof（数据），而不是sizeof的（数据*）因为你的数据结构分配空间？

Shouldn't that be sizeof(data) instead of sizeof(data*) since you're allocating space for data structures?

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