初学C：错误：控制到达非void函数的结束？ [英] Beginner C: error: control reaches end of non-void function?

问题描述

我试图做一个贪心算法，我得到这个错误：

I'm trying to make a greedy algorithm and I get this error:

greedy2.c:27:1: error: control reaches end of non-void function
      [-Werror,-Wreturn-type]
}
^
1 error generated.

本code：

int man(int argc, char* argv[])
{

  float amount;
  do
    {
      printf("Input dollar amount owed:\n");
      amount = GetFloat();
    }
  while (amount <= 0);    
  int coins = 0;
  while (amount >= 0.25);
  {
    amount = amount - 0.25;
    coins++;
  }
  printf("Number of coins to use: %d\n", coins);

}

什么是错我的花括号，如何解决呢？

What is wrong with my curly braces, and how do I fix it?

推荐答案

要简短地回答你的问题，添加：

To answer your question briefly, add:

return 0;

结束前的main（）。

您也可以在名称中一个错字。这也可能是主，而不是人。

You also have a typo in the name. It's probably main, not man.

要给你一个较长的答案，你定义的主为返回一个整数（ INT ），但没有收益语句在它的结束，因此它不返回任何东西。

To give you a longer answer, you defined main as returning an integer (int) but have no return statement at the end of it, so it doesn't return anything.

这篇关于初学C：错误：控制到达非void函数的结束？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！