如何编译没有警告被视为错误？ [英] How to compile without warnings being treated as errors?

问题描述

问题是，同样的code在Windows编译好，是无法编译在Ubuntu上。每次我得到这个错误：

The problem is that the same code that compiles well on Windows, is unable to compile on Ubuntu. Every time I get this error:

cc1: warnings being treated as errors

现在，它的大code基础，我不喜欢固定所有的警告。

Now, it's big code base and I don't like fix all the warnings.

有什么办法，我可以不顾警告编译成功？

Is there any way I can compile successfully in spite of the warnings?

推荐答案

感谢您的所有有用的建议。我终于确信有我的code没有警告，但同样是从sqlite3的得到这样的警告：

Thanks for all the helpful suggestions. I finally made sure that there are no warnings in my code, but again was getting this warning from sqlite3:

Assuming signed overflow does not occur when assuming that (X - c) <= X is always true

这是我固定加入以下CFLAG：

which I fixed by adding the following CFLAG:

-fno-strict-overflow

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