什么％s和％d个意味着在C语言中的printf？ [英] What does %s and %d mean in printf in the C language?

问题描述

我不明白什么％S 和 D％做这个C code：

I don't understand what the %s and d% do in this C code:

for (i=0;i<sizeof(code)/sizeof(char*); i++) {
    printf("%s%d%s%d\n", "Length of String ", i, " is ", strlen(code[i]));
    str = code[i];
    printf("%s%d%s%c\n","The first character in string ", i, " is ", str[0]);
}

我是新的C语言和我的背景是在Java中。

I'm new to the C language and my background is in Java.

• 怎么做％s的％D％S％ð符号表示？


• 为什么有这么多的人？


• 就是这里用于级联代替 + ？
逗号

• What do the %s%d%s%d symbols denote?
• Why are there so many of them?
• Is the comma used here for concatenation instead of a +?

推荐答案

的printf（）系列功能用途％字符作为占位符。当％遇到，下面的printf读取字符％来决定做什么：

The printf() family of functions uses % character as a placeholder. When a % is encountered, printf reads the characters following the % to determine what to do:

%s - Take the next argument and print it as a string
%d - Take the next argument and print it as an int

见一个漂亮的图片此Wikipedia文章：格式化字符串

的 \\ n 在字符串的结尾是一个换行符/回车符。

The \n at the end of the string is for a newline/carriage-return character.

这篇关于什么％s和％d个意味着在C语言中的printf？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！