如何识别从scanf的字段分隔符？ [英] how to identify a field separator from scanf?

问题描述

我需要阅读已与数名类似下面的文本文件。

I need to read a text file which has names with numbers like below.

rENLAg:12182
TgAlKd:19773
SSqUpz:16466
QYStPh:4113
CodNhz:28920
SgoIGz:25343

我需要的字母从numbers.fscanf只分离标识的空间，而不是其他领域的分隔符。因此，我该怎么办呢？

I need to separate the letters from the numbers.fscanf only identifies spaces, but not other field separators. Therefore how do I do it?

推荐答案

一个解决方案是使用的扫描设置（请参阅进入的转换说明的 [设置] 在格式说明表）：

One solution would be to use scan sets (see the entry for Conversion specifier [set] in the format specifiers table):

char buf[7];
int i;
/* Check result of fscanf(), which returns the number
   of assignments made, to ensure both 'buf' and 'i'
   were assigned values. */
if (fscanf(fp, " %6[^:]:%d", buf, &i) == 2)
{
}

其中，％6 [^：]表示跳过任何前导空格（读取例如previous换行字符），并宣读了，但不包括第一个：字符，但不超过6个字符（至prevent缓冲区溢出）

where " %6[^:]" means skip any leading whitespace (new-line character from previous read for example) and read up to, but not including, the first : character but no more than 6 characters (to prevent buffer overrun).

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