我怎么一点超过32位移位长？ [英] How do I bit shift a long by more than 32 bits?

问题描述

好像我应该能够超过32位提供移位左操作数是一个长期执行的C / C位的移位++。但是，这似乎并没有工作，至少与G ++编译器。

It seems like I should be able to perform bit shift in C/C++ by more than 32 bits provided the left operand of the shift is a long. But this doesn't seem to work, at least with the g++ compiler.

例如：

unsigned long A = (1L << 37)

给

A = 0

这不是我想要的。我缺少的东西，或者这是不可能的？

which isn't what I want. Am I missing something or is this just not possible?

-J

推荐答案

使用类型的变量 uint64_t中（从 stdint重新尝试。 ^ h ）代替长。 uint64_t中保证是64位​​长，像您期望的行为应该。

Re-try this using a variable of type uint64_t (from stdint.h) instead of long. uint64_t is guaranteed to be 64 bits long and should behave as you expect.

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