如何通过命令行参数C程序 [英] How to pass command line arguments to a c program

问题描述

我知道如何编写的程序接受的命令行参数自从我学会了编程。我不明白的是，这些参数是如何得到他们的价值观。但愿我没有这两个混在一起，但有一种说法和参数之间的差异。一个的参数的是给函数的值时，它被称为如：美孚（A，B，C）;其中a，b，和c是值。 A 参数是其内部的功能，而被调用的值。

I've known how to write a program that accepts command line arguments ever since I learned to program. What I don't understand is how these parameters get their values. Hopefully I don't have these two mixed up but there is a difference between an argument and a parameter. An argument is the value given to the function when it is called such as: foo( a, b, c); where a, b, and c are the values. A parameter is the values that are inside the function while is being called.

所以我的问题是怎样的一个人通过命令行的参数的一个程序？我知道如何读的论点，即 ARGC 是参数的个数，的argv 是一个指向数组包含有参数，等等，等等，但我只是不知道如何给这些参数的值..串

So my question is how does a person pass command line arguments to a program? I understand how to read the arguments, that argc is the number of arguments, argv is a pointer to an array of strings containing the arguments, etc. etc. but I just don't know how to give those arguments a value..

我在寻找为C和C ++的信息。我还算是一个新手在此。

I'm looking for information for both C and C++. I'm sort of a novice at this.

推荐答案

在Windows环境中，你只是通过他们，像这样在命令行上：

In a Windows environment you just pass them on the command line like so:

myProgram.exe arg1 arg2 arg3

ARGV [1]包含ARG1等

argv[1] contain arg1 etc

主要职能将是以下内容：

The main function would be the following:

int main (int argc, char *argv[])

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