C code至圆数字 [英] C code to round numbers

问题描述

有什么办法圆数字用C？

Is there any way to round numbers in C?

我不希望使用CEIL和地板。是否有任何其他的选择吗？

I do not want to use ceil and floor. Is there any other alternative?

我碰到这个code片段来了，当我Google的答案：

I came across this code snippet when I Googled for the answer:

(int)(num < 0 ? (num - 0.5) : (num + 0.5))

上面一行总是打印值4，即使浮动NUM = 4.9。

The above line always prints the value as 4 even when float num =4.9.

请提出一个解决方案。

推荐答案

4.9 + 0.5是5.4，这不可能轮4，除非你的编译器被严重损坏。

4.9 + 0.5 is 5.4, which cannot possibly round to 4 unless your compiler is seriously broken.

我刚刚确认了一派code给出了正确答案为4.9。

I just confirmed that the Googled code gives the correct answer for 4.9.

marcelo@macbookpro-1:~$ cat round.c 
#include <stdio.h>

int main() {
    float num = 4.9;
    int n = (int)(num < 0 ? (num - 0.5) : (num + 0.5));
    printf("%d\n", n);
}
marcelo@macbookpro-1:~$ make round && ./round
cc     round.c   -o round
5
marcelo@macbookpro-1:~$

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