C程序税公式 [英] C Program Tax Equation

问题描述

我需要实现一个printf到旁边的毛重和净重打印屏幕上显示的总税收。我该怎么做呢？

 的#include＆LT;＆stdio.h中GT;
＃包括LT＆;＆stdlib.h中GT;诠释主（）{
    浮hourlyRate;
    浮小时;
    浮grossPay;
    浮动税;
    浮netPay;
    浮overTimePayment;
    INT lowTax = 0.15;
    INT highTax = 0.20;    的printf（请输入时薪：）;
    scanf函数（％F，＆安培; hourlyRate）;    的printf（请输入工作时间：）;
    scanf函数（％F，＆安培;小时）;
    如果（小时＆LT; = 40）{
    grossPay =小时* hourlyRate;
    }其他
    overTimePayment =（小时 -  40）* hourlyRate * 1.5;
    grossPay + = overTimePayment;    如果（grossPay＆LT; = 600）{            netPay = grossPay  - （grossPay * lowTax）;
            的printf（\\ N低征税净工资= $％2F \\ n，netPay）;
            }
            其他    netPay = grossPay  - （grossPay * highTax）;
    的printf（\\ N高征税净工资= $％2F \\ n，netPay）;
    的printf（你的工资总额为：％.2lf \\ n，grossPay）;    返回0;
}
 

解决方案

你有你的时间计算倒置，最好是先计算加班费。 （和一些其他错误，请参阅下您的文章评论）

 的#include＆LT;＆stdio.h中GT;
＃包括LT＆;＆stdlib.h中GT;
//命名常数
＃定义HOURS_PER_WEEK 40
诠释的main（）
{
  浮hourlyRate;
  浮小时;
  浮grossPay;
  //浮动税;
  浮netPay;
  浮overTimePayment;
  浮lowTax = 0.15;
  浮highTax = 0.20;  的printf（请输入时薪：）;
  scanf函数（％F，＆安培; hourlyRate）;
  // TODO用于检查的工作更多的时间比在一个星期，等等。
  的printf（请输入工作时间：）;
  scanf函数（％F，＆安培;小时）;
  //获取第一加班费（40小时工作周）
  如果（小时＆GT; HOURS_PER_WEEK）{
    grossPay = HOURS_PER_WEEK * hourlyRate;
    overTimePayment =（小时 -  HOURS_PER_WEEK）* hourlyRate * 1.5;
    grossPay + = overTimePayment;
  }其他{
    grossPay =小时* hourlyRate;
  }
  如果（grossPay＆LT; = 600）{
    netPay = grossPay  - （grossPay * lowTax）;
    的printf（\\ N低征税净工资= $％2F \\ n，netPay）;
  }其他{
    netPay = grossPay  - （grossPay * highTax）;
  }
  的printf（\\ N高征税净工资= $％2F \\ n，netPay）;
  的printf（你的工资总额是：$％2LF \\ n，grossPay）;
  出口（EXIT_SUCCESS）;
}
 

I need to implement a printf into displaying the total taxes on the print screen next to gross and net. How do I do this?

#include <stdio.h>
#include <stdlib.h>

int main() {
    float hourlyRate;
    float hours;
    float grossPay;
    float taxes;
    float netPay;
    float overTimePayment;
    int lowTax = 0.15;
    int highTax = 0.20;

    printf("Enter the hourly rate: ");
    scanf("%f", &hourlyRate);

    printf("Enter hours worked: ");
    scanf("%f", &hours);
    if(hours <= 40) {
    grossPay = hours * hourlyRate;
    } else
    overTimePayment = (hours - 40) * hourlyRate * 1.5;
    grossPay += overTimePayment;

    if (grossPay <= 600){

            netPay = grossPay - (grossPay * lowTax);
            printf("\nLow Taxed Net Pay = $%.2f\n", netPay);
            }
            else

    netPay = grossPay - (grossPay * highTax);
    printf("\nHigh Taxed Net Pay= $%.2f\n", netPay);
    printf("Your gross pay is: %.2lf\n", grossPay);

    return 0;
}

解决方案

You had your calculation of the hours upside-down, it is better to calculate overtime first. (and some other errors, see the comments under your post)

#include <stdio.h>
#include <stdlib.h>
// name your constants
#define HOURS_PER_WEEK 40
int main()
{
  float hourlyRate;
  float hours;
  float grossPay;
  //float taxes;
  float netPay;
  float overTimePayment;
  float lowTax = 0.15;
  float highTax = 0.20;

  printf("Enter the hourly rate: ");
  scanf("%f", &hourlyRate);
  // TODO checks for "worked more hours than are in a week", etc.
  printf("Enter hours worked: ");
  scanf("%f", &hours);
  // get pay for overtime first (40 hour week)
  if (hours > HOURS_PER_WEEK) {
    grossPay = HOURS_PER_WEEK * hourlyRate;
    overTimePayment = (hours - HOURS_PER_WEEK) * hourlyRate * 1.5;
    grossPay += overTimePayment;
  } else {
    grossPay = hours * hourlyRate;
  }
  if (grossPay <= 600) {
    netPay = grossPay - (grossPay * lowTax);
    printf("\nLow Taxed Net Pay = $%.2f\n", netPay);
  } else {
    netPay = grossPay - (grossPay * highTax);
  }
  printf("\nHigh Taxed Net Pay= $%.2f\n", netPay);
  printf("Your gross pay was: $%.2lf\n", grossPay);
  exit(EXIT_SUCCESS);
}

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