鉴于双，需要找到总共有多少位数 [英] Given a double, need to find how many digits in total

问题描述

我有一个双这不一定是正，但通常。它可以是0.xxxx000或X.xxxx00000或XX.00000或0.xxx0xxx00000，其中最终有全部为0到最后一个数字的权利。我需要跟踪的多少位有。我一直有麻烦了这一点，任何帮助？这是C

I have a double which is not necessarily positive but usually. It can be 0.xxxx000 or X.xxxx00000 or XX.00000 or 0.xxx0xxx00000, where eventually there are all 0's to the right of the last number. I need to keep track of how many digits there are. I've been having trouble with this, any help? This is C.

推荐答案

用sprintf把它变成一个字符串，你需要的数字做任何计数/测试

Use sprintf to turn it into a string and do whatever counting/testing you need to do on the digits

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