编译错误：与要求不是结构或联合错误 [英] Compile error: with request not something structure or union error

问题描述

在这个程序中，我试图创建一个结构，然后初始化与结构类型a数组，把名字和年龄到阵列中，并打印出结果。然而，当我编译文件，它说，姓名和年龄是不是结构或联合。任何人都可以发现我的错误，请，谢谢

 的#include＆LT;＆stdio.h中GT;
＃包括LT＆;＆stdlib.h中GT;/ *这些阵列只是用来给'插入'的参数，
   创造了人的数组* /
字符*名称[7] = {西蒙，苏西，阿尔弗雷德，芯片，约翰，添
          哈丽雅特};
INT年龄[7] = {22，24，106，6，18，32，24};
/ *声明你的结构，一个人在这里* /
typedef结构{
  字符*名称;
  INT年龄;
}人;静态无效插入（人** P，字符* S，INT N）{   * P =的malloc（sizeof的（人））;  静态INT nextfreeplace = 0;  / *把名字和年龄成数组参数的下一个自由的地方在这里* /
    （* P） - ＆GT;名称=秒;
    （* P） -  GT;年龄= N;  / *修改nextfreeplace这里* /
  nextfreeplace ++;
  }INT主（INT ARGC，字符** argv的）{  / *在这里声明人数组* /
   人* P [7];   //成员和年龄插入unusage阵列。
  的for（int i = 0;我7;;我++）{
    插入（安培; P [I]，名称[I]，年龄[I]）;
    P [I] = P [I + 1];
  }  / *打印人民阵列这里* /
  的for（int i = 0;我7;;我++）{
    的printf（名称：％s，年龄：％I \\ N，P [I] .names，P [I] .ages）;
  }}
 

解决方案

在声明 P 为指针数组结构。在printf的行，你解引用一次 P 与 P [I] ，但p是仍然指向一个结构，你想与来访问它的字段 - ＆GT;

 的for（int i = 0;我7;;我++）{
  的printf（名称：％s，年龄：％I \\ N，P [I]  - ＆GT;名称中的[I]  - ＆GT;年龄）;
}
 

和你在增加 I 你的循环，你不需要移动你的P [I]指针，删除 P [I] = p [I + 1]

 的for（int i = 0;我7;;我++）{
  插入（安培; P [I]，名称[I]，年龄[I]）;
}
 

In this program, I am trying to create a struct, and then initialise a array with that struct type, put name and ages into the array, and print out the results. However, when I compile the file, it says that "names" and ages" are not something structure or union. Can anyone spot my errors please. Thank you

#include <stdio.h>
#include <stdlib.h>

/* these arrays are just used to give the parameters to 'insert',
   to create the 'people' array */
char *names[7]= {"Simon", "Suzie", "Alfred", "Chip", "John", "Tim",
          "Harriet"};
int ages[7]= {22, 24, 106, 6, 18, 32, 24};


/* declare your struct for a person here */
typedef struct{
  char *names;
  int ages; 
}  person;

static void insert (person **p, char *s, int n) {

   *p = malloc(sizeof(person));

  static int nextfreeplace = 0;

  /* put name and age into the next free place in the array parameter here */
    (*p)->names=s;
    (*p)->ages=n;

  /* modify nextfreeplace here */
  nextfreeplace++;
  }

int main(int argc, char **argv) {

  /* declare the people array here */
   person *p[7];

   //insert the members and age into the unusage array. 
  for (int i=0; i < 7; i++) {
    insert (&p[i], names[i], ages[i]);
    p[i]= p[i+1];
  }

  /* print the people array here*/
  for (int i=0; i < 7; i++) {
    printf("name: %s, age:%i\n", p[i].names, p[i].ages);
  }

}

解决方案

you declare p as an array of pointer to structure. On printf line, you dereference once p with p[i], but p is still a pointer to a structure, you want to access its fields with ->

for (int i=0; i < 7; i++) {
  printf("name: %s, age:%i\n", p[i]->names, p[i]->ages);
}

And as you increment i in your for loop, you dont need to move your p[i] pointer, remove, p[i] = p[i + 1]

for (int i=0; i < 7; i++) {
  insert (&p[i], names[i], ages[i]);
}

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