这怎么可能，这个字符串的长度增加了吗？ [英] How is it possible that the length of this string is increasing?

问题描述

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

char * odd(const char * S, char * dest);

int main()
{
    char * source = "abcdefghijklmnopacegiacegi";
    unsigned int length = strlen(source);
    char dest[length];
    printf("%s\n",odd(source, dest));
}

char * odd(const char * source, char * dest)
{
    int count = 0;
    unsigned int length = strlen(source);
    for(int i = 0; i < length; i++)
    {
        if( (source[i] %2 )!= 0)
        {
            dest[count] = source[i];
            count++;
        }
    }
    return dest;
}

的目标寄存器的尺寸增大和源的长度之后产生为任何值垃圾

the size of dest increases and produces garbage for any values after the length of source

推荐答案

您必须手动包括结束 \\ 0 字符串，即在年底添加，您必须添加：

You have to manually include the ending \0 to the string, that is, at the end of add, you have to add:

dest[count] = '\0';

您知道吗，串用C长度占搜索的 \\ 0 字符。你必须包括那些在每个C字符串的末尾中的一个。如果不是，该字符串可以包含任何垃圾，直到第一个 \\ 0 将被打印出来。

You know, the length of strings in C is accounted searching for the \0 character. You have to include one of those at the end of each C string. If not, the string may contain any garbage till the first \0 that will be printed.

最后，当创建 DEST ，你还增加预留空间的长度在一个容纳，结束0字符。在的strlen 不计，结束0字符。

Finally, when creating dest, you have also to increase the length of the reserved space in one to accomodate that ending 0 character. The strlen does not count that ending 0 character.

这篇关于这怎么可能，这个字符串的长度增加了吗？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！