的char *分配分割故障 [英] Segmentation fault of char * assignment

问题描述

我是想了解字符分割故障*期间下面的程序分配在位置* P ='Z'

I was trying to understand segmentation fault for char * assignment during for the following program for at location *p = 'Z'

void main()
{
   char *p ="abcdefg";
   *p = 'Z';
}

在GOOGLE上搜索，我发现很多链接的答案如下
1.这是一个字符串文字，分配一次不能有它的价值变化
2.字符串字面量不能被分配​​到* P
3.取可changd一个malloc ...等等...

When Googled, i did find many links to answers as follows 1. This is a string literal and once assigned cannot have its value changed 2. String literals cannot be assigned to *p 3. Take a malloc which can be changd... and so on...

但我担心的是，如果字符串值不能被改变，因为它是恒定的，怎么来的，当我们换一个整数恒定值，我们不分段错误。
是否有人可以帮助我更好的理解？

But my worry was if string literals values can't be changed as it is constant, how come we don't segmentation fault when we change constant value of a integer. Can someone please help me understand this better?

-Prashanth

-Prashanth

推荐答案

这是未定义的行为。如果你有一个常量字符串，标准说，字符串可能不被修改。所以还判定是否它是可写的或不依赖于体系结构，它可以或可以不出现段错误。

It's undefined behaviour. If you have a constant string, the Standard says that string literals may not be modified. So wether it is writable or not depends on the architecture, and it may, or may not segfault.

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