ç传递一个int类型的函数吗？ [英] C Passing an int in a function?

问题描述

我在一个函数传递一个INT时，得到不正确的结果：

I am getting incorrect results when passing a int in a function:

int recruit(int var1, int re_unit, char *char_buffer, int var2) {
 int run = 1;
 int int_buffer = 0;
 printf("Test1 %d\n", var1);
 printf("Test2 %d\n", var2);
 ...
}
void some_other_function(structs, struct1[]) {
 int var1 = 0;
 int var2 = 0;
 int re_unit = 0;
 char char_buffer[] = "What ever";

 //strucs[1].first = 50 this is done in a other section

 var1 = strucs1[1].first;
 var2 = strucs1[1].first;


 recruit(var1, re_unit, char_buffer, var2);
  // Ind the full verstion of the program this function is called 2 times:
  // The first time nothing is worng, how ever the second time, the result
  // is as explaned below


  //strucs[2].first = 50 // this is done in a other section
  var1 = struct1[2].first;
  var2 = struct1[2].first;

 recruit(var1, re_unit, char_buffer, var2);

}

int main(void) {
 ...
}

现在的结果是，
 第一次
 Test1的打印：2684032，和
 Test2的打印：50

Now the results is that The first time Test1 prints: 2684032, and Test2 prints: 50

第二次
 测试1打印：2684032和
 测试2打印：50;

The second time Test 1 prints: 2684032 and Test 2 prints: 50;

他们都应该打印50。

我已经测试了struct1值[1]在功能使用的招之前。首先是50。

I have tested that the value of struct1[1].first is 50 before it's used in the function recruit.

是否有任何人知道为什么会发生这种情况？

Does any one know a reason why this could happen?

推荐答案

用C的功能未初始化的值不为0，他们只是垃圾任何记忆了在那个特定的时刻。

Uninitialized values in C's functions are not 0, they are just garbage whatever memory had at that particular moment..

#include <stdio.h>
int main()
{
    int a;
    printf("%i\n", a);
    return 0;
}

这应该表现出的理念...

That should demonstrate the idea...

希望我间preTED正确的问题。

Hopefully I interpreted the question correctly.

这篇关于ç传递一个int类型的函数吗？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！