如何使用PCRE来获取所有的比赛组？ [英] How can I use PCRE to get all match groups?

问题描述

我初出茅庐用C和我需要使用PCRE来获得的匹配。

下面是我的源$ C ​​$ C的样本：

I am inexperienced with using C, and I need to use PCRE to get matches.
Here is a sample of my source code:

int test2()
{
    const char *error;
    int   erroffset;
    pcre *re;
    int   rc;
    int   i;
    int   ovector[OVECCOUNT];

    char *regex = "From:([^@]+)@([^\r]+)";
    char str[]  = "From:[e-mail]\r\n"\
                  "From:[e-mail]\r\n"\
                  "From:[e-mail]\r\n";

    re = pcre_compile (
             regex,       /* the pattern */
             0,                    /* default options */
             &error,               /* for error message */
             &erroffset,           /* for error offset */
             0);                   /* use default character tables */

    if (!re) {
        printf("pcre_compile failed (offset: %d), %s\n", erroffset, error);
        return -1;
    }

    rc = pcre_exec (
        re,                   /* the compiled pattern */
        0,                    /* no extra data - pattern was not studied */
        str,                  /* the string to match */
        strlen(str),          /* the length of the string */
        0,                    /* start at offset 0 in the subject */
        0,                    /* default options */
        ovector,              /* output vector for substring information */
        OVECCOUNT);           /* number of elements in the output vector */

    if (rc < 0) {
        switch (rc) {
            case PCRE_ERROR_NOMATCH:
                printf("String didn't match");
                break;

            default:
                printf("Error while matching: %d\n", rc);
                break;
        }
        free(re);
        return -1;
    }

    for (i = 0; i < rc; i++) {
        printf("%2d: %.*s\n", i, ovector[2*i+1] - ovector[2*i], str + ovector[2*i]);
    }
}

在本演示中，输出仅为：

In this demo, the output is only:

0：从：regular.ex$p$[e-mail]

  1：regular.ex pressions

  2：example.com

0: From:[e-mail]
1: regular.expressions
2: example.com

我要输出的所有比赛;我该怎么办呢？

I want to output all of the matches; how can I do that?

推荐答案

我用一个类来包装PCRE使它更容易些，但pcre_exec之后，ovector包含你需要找到原始的字符串内匹配的子指标

I use a class to wrap PCRE to make this easier, but after the pcre_exec, the ovector contains the substring indexes you need to find the matches within the original string.

因此​​，这将是这样的：

So it would be something like:

#include <string>
#include <iostream>
#include "pcre.h"

int main (int argc, char *argv[])
{
    const char *error;
    int   erroffset;
    pcre *re;
    int   rc;
    int   i;
    int   ovector[100];

    char *regex = "From:([^@]+)@([^\r]+)";
    char str[]  = "From:[e-mail]\r\n"\
                  "From:[e-mail]\r\n"\
                  "From:[e-mail]\r\n";

    re = pcre_compile (regex,          /* the pattern */
                       PCRE_MULTILINE,
                       &error,         /* for error message */
                       &erroffset,     /* for error offset */
                       0);             /* use default character tables */
    if (!re)
    {
        printf("pcre_compile failed (offset: %d), %s\n", erroffset, error);
        return -1;
    }

    unsigned int offset = 0;
    unsigned int len    = strlen(str);
    while (offset < len && (rc = pcre_exec(re, 0, str, len, offset, 0, ovector, sizeof(ovector))) >= 0)
    {
        for(int i = 0; i < rc; ++i)
        {
            printf("%2d: %.*s\n", i, ovector[2*i+1] - ovector[2*i], str + ovector[2*i]);
        }
        offset = ovector[1];
    }
    return 1;
}

这篇关于如何使用PCRE来获取所有的比赛组？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！