如何动态分配的二维阵列 [英] How to dynamic allocate a two dimensional array

问题描述

我想提出在C二维数组。

I would like to make a two dimensional array in C.

例如，我做指定的地点这样的一个int型变量：

For example, I make an int type variable named place like this:

int *place;

我有一个游戏，它有像行和列变量。
我想我的地方变量是一个二维数组，它的行和列（数组的最大大小），它看起来像这样的正常的声明动态分配：

I have a game, which have variables like rows, and columns. I would like my place variable to be a two dimensional array, with dynamic allocation of its rows and columns (for the max size of the array), which would look like this in the "normal" declaration:

place[rows][columns];

但我不知道如何与动态分配去做。

but I don't know how to do it with the dynamic allocation.

我会做这样的一维数组：

I would do it like this for one-dimensional arrays:

place = (int*) malloc (levels * sizeof(int));

但我不知道如何使用二维数组做到这一点。

but I don't know how to do this with 2D arrays.

编辑：

我怎么能对字符，而不是INT改写呢？

How I can rewrite this for char instead of int?

我试图只是简单地覆盖与字符的整数，但它不能正常工作。

I have tried to just overwrite the ints with chars, but it doesn't work.

推荐答案

让地方是一个指针数组，

int (*place)[columns] = malloc(rows * sizeof *place);

这是给你的内存（好地方）一个连续的块，你可以简单地用

That gives you a contiguous block of memory (good for locality) that you can simply access with

place[i][j] = whatever;

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