我该如何重新present一个统一code字符文本字符串ISO / ANSI C时，字符集是ASCII？ [英] How do I represent a Unicode character in a literal string ISO/ANSI C when the character set is ASCII?

问题描述

在Perl中，我可以说

 我的$ S =r \\ X {} E9总和\\ X {E9};
 

分配简历到 $ S 。我想要做C.类似的东西我特别想说

  sometype_that_can_hold_utf8 C = get_utf8_char（）;
如果（℃下'\\ X {E9}'）{
    /* 做一点事 */
}
 

解决方案

有关UTF8，你必须使用规则中，例如生成自己的编码，的此处。例如，德国的sharp s（SS，code点0xdf），具有UTF8编码0xc3,0x9f。您的E-急性（E，code点0xe9）有0xc3,0xa9的UTF8编码。

你可以把任意的十六进制字符在你的字符串有：

 的char * CV =r \\ XC3 \\ xa9sum \\ XC3版权所有\\ xA9
字符*锐器=\\ XC3 \\ x9f
 

In Perl, I can say

my $s = "r\x{e9}sum\x{e9}";

to assign "résumé" to $s. I want to do something similar in C. Specifically, I want to say

sometype_that_can_hold_utf8 c = get_utf8_char();
if (c < '\x{e9}') {
    /* do something */
}

解决方案

For UTF8, you have to generate the encoding yourself using rules found, for example, here. For example, the German sharp s (ß, code point 0xdf), has the UTF8 encoding 0xc3,0x9f. Your e-acute (é, code point 0xe9) has a UTF8 encoding of 0xc3,0xa9.

And you can put arbitrary hex characters in your strings with:

char *cv = "r\xc3\xa9sum\xc3\xa9";
char *sharpS = "\xc3\x9f";

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