的getchar()最多和向下箭头键返回相同的值(27) [英] getchar() returns the same value (27) for up and down arrow keys
问题描述
因此,对于键盘上的向上键,我得到27,令人惊讶的向下键我也得到27.我需要我的程序来表现不同的上下键,我似乎无法弄清楚。我使用Linux,并且需要它为Linux工作。
的#include<&stdio.h中GT;
#包括LT&;&stdlib.h中GT;
#包括LT&;&string.h中GT;
#包括LT&;&文件ctype.h GT;
诠释的main()
{
INT C =的getchar(); 如果(C == 27)
{
的printf(UP);
} 如果(C == 28)
{
的printf(DOWN);
}}
的 27
意味着你得到的箭头ANSI转义序列。他们将是三个字符的序列:27,91,然后65,66,67,68(IIRC)的上,下,左,右。如果你收到了 27
从调用的getchar()
,然后调用它两次获得 91
并确定哪些箭头键是pressed数量。
至于别人提到的,这是特定于平台的,但你可能没在意。
So for the up key on the keyboard, I get 27, surprisingly for the down key I also get 27. I need my program to behave differently on the up and down key, and I can't seem to figure it out. I am using Linux, and need it to work for Linux.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>
int main()
{
int c = getchar();
if(c==27)
{
printf("UP");
}
if(c==28)
{
printf("DOWN");
}
}
The 27
implies that you're getting ANSI escape sequences for the arrows. They're going to be three-character sequences: 27, 91, and then 65, 66, 67, 68 (IIRC) for up, down, right, left. If you get a 27
from a call to getchar()
, then call it twice more to get the 91
and the number that determines what arrow key was pressed.
As someone else mentioned, this is platform-specific, but you may not care.
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