一元减号和浮充转换的组合 [英] combination of unary minus and float conversion
问题描述
考虑下面的C语句:
unsigned long x = 1;
float a = -x;
double b = -x;
我希望一元减术语,以产生一个unsigned long值等于ULONG_MAX和A和B分别设为ULONG_MAX的单,双precision重新presentations。
I would expect the unary minus term to yield an unsigned long value equal to ULONG_MAX and a and b to be set to single and double precision representations of ULONG_MAX, respectively.
这是结果我与32位Linux,并与64位Linux的英特尔和PGI编译器GCC 4.4.7获得。与海湾合作委员会的64位Linux(测试版本4.4.7,4.7.2和4.8.0,都与-O0和-O2),然而,双变量B的预期值,但浮动等于-1来代替。
This is the result I obtain with gcc 4.4.7 on 32-bit Linux and with the Intel and PGI compilers on 64-bit Linux. With gcc (tested versions 4.4.7, 4.7.2 and 4.8.0, both with -O0 and -O2) on 64-bit Linux, however, the double variable b has the expected value, but float a becomes equal to -1 instead.
相反,下面的语句将A和B都设置为浮动ULONG_MAX点重新presentations所有的编译器和系统我测试:
By contrast, the following statements will set both a and b to floating point representations of ULONG_MAX on all compilers and systems I tested:
unsigned long x = 1;
unsigned long y = -x;
float a = y;
double b = y;
如果我使用unsigned int类型,而不是无符号长的,我得到的所有系统上的预期的结果了。
If I use unsigned int instead of unsigned long, I get the expected result on all systems, too.
这是某种不确定的行为或编译器错误?
Is this some kind of undefined behaviour or a compiler error?
推荐答案
这是由于错误的GCC - 否定之前的类型转换发生
This is due to a bug in GCC -- the type conversion happens before the negation.
这个问题似乎已经存在了一段时间。 错误55771 - 否定与类型转换错误交换
The issue seems to be have been around for a while. Bug 55771 - Negation and type conversion incorrectly exchanged
在第二个例子中,否定类型转换之前发生。因此,你看到预期的效果。
In your second example, the negation happens before the type conversion. As such, you see expected results.
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