Ç不兼容的类型中分配，使用指针的问题？ [英] c incompatible types in assignment, problem with pointers?

问题描述

你好，我用C工作，我有一个关于分配问题的指针。

Hi I'm working with C and I have a question about assigning pointers.

struct foo
{
   int _bar;
   char * _car[SOME_NUMBER]; // this is meant to be an array of char * so that it can hold pointers to names of cars
}

int foofunc (void * arg)
{
   int bar;
   char * car[SOME_NUMBER];

   struct foo * thing = (struct foo *) arg;

   bar = thing->_bar; // this works fine
   car = thing->_car; // this gives compiler errors of incompatible types in assignment
}

汽车_car具有相同的声明，那么为什么我会收到关于不兼容类型的错误？我的猜测是，它有话跟他们是指针（因为它们是指向char *数组，对吧？），但我不明白为什么这是一个问题。

car and _car have same declaration so why am I getting an error about incompatible types? My guess is that it has something to do with them being pointers (because they are pointers to arrays of char *, right?) but I don't see why that is a problem.

当我宣布的char *车; 而不是中的char *汽车[MAXINT]; 它编译的罚款。但我不明白如何当我需要使用索引，这将是非常恼人稍后访问信息访问某些信息，这将是对我有用更高版本。事实上，我甚至不知道如果我要了解正确的方式，也许有存储一串字符串，而不是使用字符数组的一种更好的方式*？

when i declared char * car; instead of char * car[MAXINT]; it compiles fine. but I don't see how that would be useful to me later when I need to access certain info using index, it would be very annoying to access that info later. in fact, I'm not even sure if I am going about the right way, maybe there is a better way to store a bunch of strings instead of using array of char *?

编辑：我不是故意用INT_MAX（INT的最大值），它只是一些其他的INT，也就是约20

I didn't mean to use INT_MAX (maximum value of int), it's just some other int, which is about 20.

推荐答案

您正在创建规模MAXINT的新数组。我想你想创建一个指向大小MAXINT的数组。

You are creating a new array of size MAXINT. I think you want to create a pointer to an array of size MAXINT.

创建一个指向字符数组*的：

以下是规模最大整数数组为char *元素：

The following is an array of size MAXINT to char* elements:

char * car[MAXINT]; 

下面是一个指向：大小MAXINT的数组为char *元素：

The following is a pointer to: an array of size MAXINT to char* elements:

char* (*car)[MAXINT];

以下是你如何设置一个指向：大小MAXINT的数组为char *元素：

the following is how you set a pointer to: an array of size MAXINT to char* elements:

char* (*car)[MAXINT];
car = &arg->_car;

---

在这个问题其他语法错误：

• 您需要您的结构定义后有一个分号。


• 您应该使用富* 不是富。因此它应该是：搜索
  结构美孚*的东西=（结构美孚*）ARG;


• 您应该使用的事情不是 ARG ：结果
  酒吧=东西─＆GT; _bar; 结果
  汽车=东西─＆GT; _car;

• You need to have a semicolon after your struct definition.
• You should be using foo* not foo. So it should be:
  struct foo* thing = (struct foo *) arg;
• You should be using thing not arg:
  bar = thing->_bar;
car = thing->_car;

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