是否有可能一个雨燕类转换成C的void *指针？ [英] Is it possible to convert a Swift class into C void* pointer?

问题描述

是否有可能一个雨燕类转换成C的void *指针？

Is it possible to convert a Swift class into C void* pointer?

// swift class
 class MyClass {

 }

var myClass = MyClass()
var p: UnsafeMutablePointer<Void> = myClass //<- failed

//c function 
void someSwiftClass(void *context);

感谢

推荐答案

我有类似的问题，你可以如下转换这一点。

I had similar problem, you can convert this as below.

var myClass = MyClass()

var classPtr = unsafeBitCast(myClass, UnsafePointer<Void>.self)    

和你的函数，

func someSwiftClass(voidPointer: UnsafeMutablePointer<Void>) {

}

如果要声明常量指针使用 UnsafePointer＆LT; T＆GT; ，当你的指针是不是经常使用 UnsafeMutablePointer＆LT; T＆GT;

If you want to declare constant pointer use UnsafePointer<T> and when your pointer is not constant use UnsafeMutablePointer<T>

在C常量指针 - const int的* myCpointer

In C constant pointer - const int *myCpointer

相应迅速指针 - 让mySwiftPointer：UnsafePointer＆LT;＆的Int32 GT;

Corresponding swift pointer - let mySwiftPointer: UnsafePointer<Int32>

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