显示precedes数输入。 （C编程） [英] display that precedes the number entered. (C programming)

问题描述

C语言程序设计

要求用户1和100之间选择一个随机数，然后问他要多少个号码，以显示他进入该precedes第一个号码。

Ask user to enter a random number between 1 and 100. Then ask how many numbers he wants to display that precedes first number he enters.

让用户是否进入9，并希望3个数字是precedes 9，你的程序应该显示这个说：
•6 7 8 9

Let’s say if user enter 9 and wants 3 numbers that precedes 9, your program should display this: • 6 7 8 9

不知道需要一些帮助。

推荐答案

有关询问用户一个问题，你可以使用像的printf 或看跌。

For asking the user a question, you can use something like printf or puts.

要请求号的从的用户， scanf函数是可能是你在工作级别的最佳方法。

To request numbers from the user, scanf is probably the best approach for the level you're working at.

举例来说，下面是要求用户的号码，然后给他们下一个数一个完整的程序：

By way of example, here's a complete program that asks the user for a number then gives them the next number:

#include <stdio.h>

int main (void) {
    int num;
    printf ("Enter a number: ");
    if (scanf ("%d", &num) != 1) {
        puts ("That wasn't a valid number");
        return 1;
    }
    printf ("The next number is %d\n", num + 1);
    return 0;
}

浅析了code和它做什么它运行的时候，应该足以让你开始。

Analysing that code, and what it does when it runs, should be enough to get you started.

有关您的具体项目，下面的伪code应该有所帮助：

For your specific project, the following pseudo-code should help:

print "Enter the ending number: "
input endnum
print "Enter the count of preceding numbers: "
input count

num = endnum - count
do:
    print num
    num = num + 1
while num <= endnum

这是你可以使用的算法，我不会为它为C code，因为如果你这样做你自己，你会成为一个更好的$ C $铬。在任何情况下，那些伪code线全部pretty多有一个一对一的映射与C语句，所以应该是比较容易得到的东西去。

That's the algorithm you can use, I won't provide it as C code since you'll become a better coder if you do that yourself. In any case, those pseudo-code lines all pretty much have a one-to-one mapping with C statements so it should be relatively easy to get something going.

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