如何找到没有原型C函数？ [英] How to find C functions without a prototype?

问题描述

公司的政策规定，在C源$ C ​​$ C每个函数都有一个原型。我继承了一个项目，其自身的使系统（所以我的不能测试它GCC或Visual Studio），发现其中一个文件有没有原型声明的一些静态功能。有没有一种方法（不一定与编译器）列出所有功能，而原型中的所有.c文件？

Company policy dictates that every function in C source code has a prototype. I inherited a project with its own make system (so I cannot test it on gcc or Visual Studio) and found that one of the files has some static functions declared without prototypes. Is there a way (not necessarily with a compiler) to list all functions without prototypes in all .c files?

推荐答案

gcc有一个选项来提醒你一下：

gcc has an option to warn you about this:

gcc -Wmissing-prototypes

您可以关闭该警告变成了错误，停止编译和力量的人来解决它：

You can turn this warning into an error to stop compilation and force people to fix it:

gcc -Werror=missing-prototypes

如果你只是想列出它，你可以用 GCC 选项 -Wmissing的原型和grep的编译否previous原型在日志中。

If you just want to list it you can compile with the gcc option -Wmissing-prototypes and grep for no previous prototype for in the log.

基于编辑更新

既然你现在提到，你不能用gcc，你必须找到你当前的编译器的类似选项。大多数编译器有这样一个选项。先从手册页或内置的帮助输出。

Since you now mention that you can't use gcc, you'll have to find a similar option for your current compiler. Most compilers have such an option. Start with the man page or the built in help output.

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