转换的std ::列表到C型友好 [英] Converting std::list to C friendly type

问题描述

什么是最优雅的方式从一个共享库函数（由C ++ code实现）为C消费者返回的std ::列表对象吗？我知道的std ::矢量，我们可以返回矢量的第一个元素的地址，并有消费者把它当作一个数组，但性病::清单实施作为链接LIS。

What's the most elegant way to return a std::list object from a shared lib function (implemented by C++ code) to a C consumer? I know for std::vector, we can return the address of the 1st element of the vector and have the consumer treat it as an array, but std::list is implemented as a linked lis.

推荐答案

的的std ::列表复制到的std ::矢量，返回的第一个元素的地址，因为你已经提到。

Copy the std::list to a std::vector and return the address of the first element, as you already mentioned.

（当然，这可能意味着你不想使用摆在首位一个的std ::列表来定。）

(Of course, this may mean that you don't want to be using a std::list in the first place.)

（该解决方案假设所访问的对象是的拥有的由C ++库 - 如果不是这种情况，你可能需要考虑从C code分配内存并将指针传递到C ++库来复制数据。）

(This solution assumes that the object being accessed is owned by the C++ library -- If this isn't the case, you may need to consider allocating the memory from your C code and passing a pointer into the C++ library to copy the data.)

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