要实现超时在C一个函数 [英] Want to Implement Timeout for one function in C

问题描述

在这里，我有一个函数，它是监听模式。此功能列出一些东西，我得到了一些形成设备。

Here i have one function which is listen mode. this function listing something which i got form some device.

下面时，我的功能是听那个时候我想创建超时模式。如果我不会得到来自特定设备的任何回应，比我想从这个函数O退出，必须通知。

Here when my function is in listen mode that time i want to create timeout. if i will not get any response from particular device than i want o exit from this function and have to notify.

如果超时期间，如果我会从设备响应比我继续工作，并停止该超时并没有限制完成任何持续时间这项工作。

if during this timeout period if i will get response from device than i have to continue with work and stop this timeout and there is no limits to complete this work in any time duration.

那么，怎样才能实现我这个东西的功能。

So how can i implement this thing for a function.

任何机构可以请我帮我实现这个东西带超时功能。

Any body please can me help me to implement this thing with timeout functionality.

推荐答案

看看 2人报警。您可以设置或关闭，这将在一定时间之后经过一段发送到您的应用程序的信号。

Take a look at man 2 alarm. You can set or disable signals which will be sent to your application after a certain time period elapses.

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