分配给自己:优化或多余的? [英] Assign to itself: optimization or extraneous?
本文介绍了分配给自己:优化或多余的?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
所以我要通过非官方OpenGL库的glimg部分和整个东西来到我发现了奇怪的。在功能一个指针参数被分配给它,我看不出这可以完成任何事情。这是否在某种程度上迫使内存入高速缓存,或者是别的东西吗?可能是一个错误吗?
静态UINT8 * resample_row_generic(UINT8 *总分,UINT8 * in_near,UINT8 * in_far,诠释W,诠释HS)
{
//与近邻重采样
INT I,J;
in_far = in_far; //< - 在这里?
对于(i = 0; I<瓦; ++ I)
为(J = 0; J< HS; ++ j)条
出[我* HS + J] = in_near [I]
返回的;
}
解决方案
这是那里共进晚餐preSS的警告参数 in_far
在函数不使用
共进晚餐preSS警告另一种方法是:
(无效)in_far;
So I was going through the glimg section of the unofficial OpenGL library and came across something I found strange. In one of the functions a pointer parameter is being assigned to itself and I can't see how this could be accomplishing anything. Does this somehow force memory into cache or is it something else? Possibly a bug?
static uint8 *resample_row_generic(uint8 *out, uint8 *in_near, uint8 *in_far, int w, int hs)
{
// resample with nearest-neighbor
int i,j;
in_far = in_far; // <-- here?
for (i=0; i < w; ++i)
for (j=0; j < hs; ++j)
out[i*hs+j] = in_near[i];
return out;
}
解决方案
It's there to suppress the warning that the parameter in_far
is not used in the function.
Another way to suppress the warning is:
(void)in_far;
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