RPC客户端提供了无法连接code参数 [英] RPC Client gives Can't encode arguments

问题描述

我试图写的RPC客户端simpliest此code：

I'm trying to write the simpliest client in RPC with this code:

#include <stdio.h>
#include <stdlib.h>
#include <rpc/rpc.h>

int main(int argc, char *argv[]){
  int stat;
  char out;
    char in='f';

  if(stat=callrpc(argv[1],0x20000001, 1, 1, (xdrproc_t)xdr_void, &in, (xdrproc_t)xdr_char, &out)!=0){
      clnt_perrno(stat);
      exit(1);
  }

  exit(0);
}

它编译，但是当我尝试运行它，它给了我一个RPC：无法连接code参数

It compiles, but when I try to run it, it gives me a "RPC: Can't encode arguments"

编辑：其实服务器没有收到任何说法既不它发回任何东西，这就是为什么我把 xdr_void 添加＆功放;在和＆放大器;退出来避免分段错误

Actually the server do not recieve any argument neither it send back anything, that's why I put a xdr_void added &in and &out to avoid segmentation fault error.

推荐答案

您缺少一些括号：

if (stat = callrpc(...) != 0)

进行评估，以<​​/ P>

is evaluated to

if (stat = (callrpc(...) != 0))

它总是分配 1 到与stat 中的错误，这是的情况下， RPC_CANTEN codeARGS 。您需要

which always assigns 1 to stat in case of an error, which is RPC_CANTENCODEARGS. You need

if ((stat = callrpc(...)) != 0)

要得到真正的错误code和消息

to get the real error code and message printed in

clnt_perrno(stat);

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