C，传递结构作为参数 [英] c, passing struct as argument

问题描述

我需要通过一些结构，这样的函数参数

I need to pass some structure as function argument like this

void myFunc(unsigned char c);

我将使用 myFunc的（4）， myFunc的（8）左右。

现在函数接受结构参数，所以我试图

Now the function accepts a structure as argument, so I tried

typedef struct {
    unsigned char address;
    unsigned char command;
    unsigned char group;
    unsigned char response;
    unsigned char flags1;
    unsigned char flags2;
}test_t;

void myFunc(test_t test);

myFucn({0,0,0,0,0}); // but this gives me error 

我如何能够通过常量结构作为无参数，必须先实例化？
就像myFunc的（4）无符号字符。

How can I pass const struct as argument without to have to instantiate first ? Just like myFunc(4) as unsigned char.

感谢

推荐答案

在C99中，您可以使用复合文字：

In C99, you can use a compound literal:

myFunc((test_t) { 0, 0, 0, 0, 0 });

当然，由于该结构被按值传递的，它不会，如果你认为它是常量或没有关系;不管该函数来都不会有问题到外部。

Of course, since the struct is being passed by value, it doesn't matter if you consider it to be "const" or not; whatever the function does to it won't matter to the outside.

在的C previous版本中，你不能做到这一点。

In previous versions of C, you cannot do this.

这篇关于C，传递结构作为参数的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！