用C的char []和char *之间的区别 [英] Difference between char[] and char * in C

问题描述

什么是用C的char [] S和char * S之间的区别？
据我了解，双方建立做出的指针字符数组。
不过，

What is the difference between char[] s and char * s in C? I understand that both create make 's' a pointer to the array of characters. However,

char s[] = "hello";
s[3] = 'a';
printf("\n%s\n", s);

打印 helao ，而

char * s = "hello";
s[3] = 'a';
printf("\n%s\n", s);

给我一个分段错误。为什么会有这样的区别？
我使用Ubuntu的12.04 GCC。

gives me a segmentation fault. Why is there such a difference? I'm using gcc on Ubuntu 12.04.

推荐答案

在使用个char [] =你好; ，在范围内创建的字符数组目前的功能，因此内存堆栈上进入函数时分配的。

When using char s[] = "hello";, the char array is created in the scope of the current function, hence the memory is allocated on the stack when entering the function.

在使用的char * s =你好; ，取值是一个指向一个常量字符串，它的编译器保存在其中被阻止写访问的程序的内存块，因此分段错误。

When using char *s = "hello";, s is a pointer to a constant string which the compiler saves in a block of memory of the program which is blocked for write-access, hence the segmentation fault.

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