使用scanf的函数执行C-程序时，空consolewindow [英] empty consolewindow when executing c-programs using scanf-function

问题描述

我真的很新的C语言。我有以下问题。

I am really new to c-language. I have the following problem.

如果我用scanf（）的 - 功能的程序似乎没有正确执行。我使用Eclipse和控制台窗口是空的。可是 - 当我termine的C程序一切都显示在控制台窗口了。

If I use scanf()-function the program does not seem to execute properly. I am using Eclipse and the console window is empty. BUT - when I termine the c-program everything is showing up in the console-window.

#include<stdio.h>
#include<conio.h>

void main()
{
  int i;
 char c;
 char s[10];
 float f;

 printf("Enter an integer number:");
 scanf("%d",&i);
 fflush(stdin);
 printf("Enter string:");
 scanf("%s",s);
 fflush(stdin);
 printf("Enter a floating number:");
 scanf("%f",&f);
 fflush(stdin);
 printf("Enter a character:");
 scanf("%c",&c);

 printf("\nYou have entered \n\n");
 printf("integer:%d \ncharacter:%c \nstring:%s \nfloat:%f",i,c,s,f);
 getch();
}

是什么原因？

推荐答案

标准输出，其中的printf（）写道：到时，行缓冲，所以它遇到一个 \\ n 。

stdout, which printf() writes to, is line buffered, so it is only flushed when encountering a \n.

所以，让你的输入提示出现，你需要显式冲水标准输出：

So to have your input prompts appear, you need to explictly flush stdout:

printf("Enter an integer number:");
fflush(stdout);
scanf("%d", &i);

---

在程序缓冲区刷新隐含终止，这就是为什么的printf（） ED数据持续出现在节目结束在控制台上。

---

On termination of the program buffers are implicitly flushed, that's why printf()ed data lasted appear on the console when the program has ended.

不过，从源头上您发布应该有打印到控制台数据后，该行一直执行：

However, from the source you post there should be data printed to the console after this line had been execute:

printf("\nYou have entered \n\n");

由于有 \\ n 秒。所以，我想你不告诉我们确切的code。

As there are \ns. So I assume you do not show us the exact code.

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