While循环跳过它的病情scanf函数。 [英] While Loop skipping scanf for it's condition.

问题描述

我不明白为什么While循环不仅仅是速度，距离跳过scanf函数的字符？
它甚至不问我的投入，只是环像没有明天。

I can't see why does the While loop just speed away and skipping the scanf for the char? It would not even ask for my input and just loop like there's no tomorrow.

#include <stdio.h>


int main()
{
    int number;
    int multiply, ans;
    char choice;

    printf("-------------------------------------");
    printf("\n      MULTIPLICATION TABLE           ");
    printf("\n-------------------------------------");


    do
    {

         printf("\nEnter an integer number:");
         scanf("%d", &number);


        printf("\nMultiplication of %d is :-\n", number);
        printf("\n");

        for(multiply=1; multiply<11; multiply++){
            ans = number * multiply;
            printf(" %d", ans);
        }

        printf("\n");
        printf("\nWould you like to continue? [Y] for Yes,[N] for no : ");
        scanf("%c", &choice);
        printf("\n");

    } 
    while(choice='Y');

    printf("Thank You");
    return 0;

}

推荐答案

scanf（）的不会做你认为它（换行字符，缓冲等）。这是pferred使用$ P $ 龟etc（）：

scanf() doesn't do what you think it does (newline characters, buffering, etc.). It's preferred to use fgetc():

choice = fgetc(stdin);

出于同样的原因，你需要摆脱尾随换行符的

For the same reason, you need to get rid of the trailing newline that

scanf("%d", &number");

叶在标准输入缓冲区。为了解决这个问题，插入

leaves in the standard input buffer. To fix this, insert

fgetc(stdin);

到 scanf函数是特定的呼叫后（）。

另外，C是不帕斯卡。平等比较运营商 - 和条件 - 你要找的是

Also, C is not Pascal. The equality comparison operator - and the condition - you're looking for is

while (choice == 'Y')

单方程标记表示赋值。

the single equation mark denotes an assignment.

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