sprintf的格式说明由什么代替 [英] sprintf format specifier replace by nothing

问题描述

我目前不知道是否有一种方法通过使用无sprintf的更换格式说明％U

I am currently wondering if there is a way to replace the format specifier %u by nothing using sprintf

我的问题是关于sprintf的使用三元运算符的这要去一个值或空字符替换％U

My question is about the use of a ternary operator in sprintf which gonna replace %u by a value or by nothing.

下面是什么，我试图做一个例子：

Here is an example of what I am trying to do :

int main (void)
{
   char mytab[10]={'\0'};
   uint_32 i=0;

   scanf("%u",&i);

   sprintf(mytab, "\"%u"\",i>0?i:/*Here is the syntax I want to find if it exists*/);
   printf("%s\r\n",mytab);

   return 0;
}

在code我想获得的结果是，例如1，如果输入为1（或2，如果输入是2 ......）和如果输入为0。

The result of the code I am trying to get is for example "1" if the input is 1 (or "2" if the input is 2...) and "" if the input is 0.

你对此有任何意见或explantion？由于提前通过

Do you have any ideas or explantion about it ? Thanks by advance.

推荐答案

我想一个简单的如果语句仍然是最干净的选项：

I think a simple if statement is still the cleanest option:

char mytab[10] = "\"\"";

if (n > 0) {
    snprintf(mytab, sizeof mytab, "\"%" PRIu32 "\"", n);
}

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