利用字符串的指针打印的字符组合的整数 [英] making use of string pointer to print the character-integer combinations

问题描述

我有C函数接受字符串指针作为参数。这个功能返回如符号是由该指针指向。我想生成取决于需求=很多符号。假设，我有四个门的房子。我想给不同的名称不同的门像 D1，D2，D3 ...... 。在这种情况下，我想创建一个字符串指针，它指向字符串和整数，这样我就可以得到它通过只数值不同的符号。这有助于我看到分类的字符串值的符号。我想知道我可以声明一个字符串指针，这样我可以创造我上面提到的象征。

I have C function that takes string pointer as a parameter. This functions returns as symbol which is pointed by the pointer. I would like to generate = many symbols depending upon the requirements. Suppose, i have four doors in a house. I would like to give different names to different doors like d1,d2,d3..... In this case , i would like to create a string pointer which points to both string and integer so that i can get the symbols which differ by only numerical values. This helps me to categorize the symbols seeing the string value. I would like to know how can i declare a string pointer so that i can create a symbol that i mentioned above.

我会尽量说清楚。

我有两个指针数组

const char *test[] ={"a","12345"}

我想使指针指向一个1和和2 ....等等。有没有什么方法呢？

I would like make the pointer to point a and 1 and a and 2 and .... so on. Is there any method to do it?

推荐答案

既然问题是如此暧昧，这里是另一个之一：

Since the question is so ambiguous, here's yet another one:

#include <stdio.h>

int main(int argc, char *argv) {
    const char *test[] = { "a", "12345" };

    int i, j;

    for (i = 0; test[0][i] != 0; ++i)
        for (j = 0; test[1][j] != 0; ++j)
            printf("%c%c\n", test[0][i], test[1][j]);

    return 0;
}

输出：

a1
a2
a3
a4
a5

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