通过与指针数组循环？ [英] Loop through an array with pointers?

问题描述

我想了解指针这是一个真正皮塔饼时，你不太完全了解它。

I am trying to learn pointers which is a real PITA when you don't quite fully understand it.

我要打印的阵列中的所有元素，但只有在打印的第一要素。

I am trying to print all the elements in the array but only the first element is printed.

#include <stdio.h>

int count(const int* numbers, int size)
{
    for(; numbers < size; numbers++)
    {
        printf("%d", *numbers);
    }
}

int main(void)
{

    int numbers[] = {3, 4, 6, 3, 46};

    int result = count(numbers, 5);

    printf("%d\n", result);

    return 0;
}

在循环中的计数的功能似乎并没有正常工作，因为它只能通过一次循环，但我不明白为什么。

The loop in the count function does not seem to work properly since it is only looping through one time but I can't understand why.

推荐答案

比较数字＆LT;大小是错误的。

您有3种选择：

1. 有一个单独的索引变量：

1. Have a separate index variable:

int count;
for(count = 0; count < size; count++)
{
    printf("%d", numbers[count]);
}

有一个单独的光标指针：

Have a separate "cursor" pointer:

const int * const end = numbers + size;
for(; numbers < end; numbers++)
{
    printf("%d", *numbers);
}

递减尺寸：

for(; size != 0; size--, numbers++)
{
    printf("%d", *numbers);
}

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