如何能结构用于重新present复数 [英] How can structures be used to represent complex numbers

问题描述

我需要写它使用结构来定义复杂的数字，即Z1 = X +易的程序。然后添加2复数。我需要弄清楚如何与我的code移动之前正确initalise他们。我已经尝试了一些事情，到目前为止，这是我想出最好的，它仍然没有编制。

下面是我的code的副本，我只需要解决这个问题的一部分，那么我就可以完成剩下的我自己。

 ＃包括LT＆;＆stdio.h中GT;typedef结构complex1 {
    浮* real1;
    浮* imaginary1;
} complex1;
typedef结构complex2 {
    浮* REAL2;
    浮* imaginary2;
} complex2;
诠释主（）{
  结构complex1实;
  结构complex1 * realptr;
  结构complex1虚;
  结构complex1 * imaginaryptr;
  结构complex2实;
  结构complex2 * realptr;
  结构complex2虚;
  结构complex2 * imaginaryptr;  的printf（请输入变量X1。）;
  scanf函数（％d个，＆安培; real.real1）;
  的printf（请输入变量Y1。）;
  scanf函数（％d个，＆安培; imaginary.imaginary1）;
  的printf（请输入变量X2）;
  scanf函数（％d个，＆安培; real.real2）;
  的printf（请输入变量Y2。）;
  scanf函数（％d个，＆安培; imaginary.imaginary2）;
  的printf（你输入：％D，％D，％D，％d个\\ N，
  real.real1，imaginary.imaginary1，real.real2，imaginary.imagnary2）;
  返回0;
}
 

解决方案

有文件中的多个错误，但也许这样的事情更是你想要什么？

 ＃包括LT＆;＆stdio.h中GT;typedef结构_complex1 {
    双real1;
    双imaginary1;
} complex1;
 

不要使用相同的名称命名结构两次，我相信你想跳过real1和imaginary1指针 - 因为他们没有得到你什么

  INT的main（）{
  complex1实;
  complex1 * realptr;
  complex1虚;
  complex1 * imaginaryptr;
  complex2 REAL2;
  complex2 * realptr2;
  complex2 imaginary2;
  complex2 * imaginaryptr2;
 

复杂类型定义已经告诉编译器，它是一个结构。而且你不能有两个同名变量。

 的printf（请输入变量X1。）;
  scanf函数（％LF，＆安培; real.real1）;
 

您需要调整您发送什么，它预计scanf函数是什么。 ％F预计双*，而不是双**或（浮动**你的情况）。

I need to write a program which uses structures to define complex numbers ie z1 = x + yi. And then adds 2 complex numbers. I need to figure out how to initalise them properly before moving on with my code. I've tried a few things so far, this is the best I have come up with and it's still not compiling.

Here's a copy of my code, I just need to fix this part and then I will be able to do the rest myself.

#include<stdio.h>

typedef struct complex1{
    float *real1;
    float *imaginary1;
} complex1;


typedef struct complex2{
    float *real2;
    float *imaginary2;
} complex2;


int main(){
  struct complex1 real;
  struct complex1 *realptr;
  struct complex1 imaginary;
  struct complex1 *imaginaryptr;
  struct complex2 real;
  struct complex2 *realptr;
  struct complex2 imaginary;
  struct complex2 *imaginaryptr;

  printf("Please enter variable x1.");
  scanf("%d", &real.real1);
  printf("Please enter variable y1.");
  scanf("%d", &imaginary.imaginary1);
  printf("Please enter variable x2.");
  scanf("%d", &real.real2);
  printf("Please enter variable y2.");
  scanf("%d", &imaginary.imaginary2);
  printf("You have entered: %d,%d,%d,%d\n", 
  real.real1, imaginary.imaginary1,real.real2, imaginary.imagnary2);
  return 0;
}

解决方案

There were multiple errors in the file, but maybe something like this is more what you want ?

#include<stdio.h>

typedef struct _complex1{
    double real1;
    double imaginary1;
} complex1;

Do not name the struct twice with the same name, and I do believe you want to skip the pointers for real1 and imaginary1 -- since they do not gain you anything.

int main(){
  complex1 real;
  complex1 *realptr;
  complex1 imaginary;
  complex1 *imaginaryptr;
  complex2 real2;
  complex2 *realptr2;
  complex2 imaginary2;
  complex2 *imaginaryptr2;

The complex typedefs already tell the compiler that it is a struct. And you can not have two variables with the same name.

  printf("Please enter variable x1.");
  scanf("%lf", &real.real1);

You need to align what you are sending to scanf with what it expects. %f expects a double * and not a double ** or (float ** in your case).

这篇关于如何能结构用于重新present复数的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！