对于循环运行额外的时间超过规定是什么？ [英] For loop runs an extra time than what is specified?

问题描述

那么，我的code的作用是，它需要在数量和输出所有的数字连续滚动平均值的列表。我scanf的函数运行，所以我只是把零一个额外的时间。我该如何解决这个问题？以下是我有：

So what my code does is that it takes in a list of numbers and outputs consecutive rolling average of all the numbers. My scanf function runs an extra time so I just put in a zero. How can I fix this? Here is what I have:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main(){
    int i,n;
    double numbers[100]; double previous[100]; double x[100];
    double mean[100]; double old_average[100]; double new_average[100];
    printf("Total amount of numbers: ");
    scanf("%d\n", &n);
    for (i=1; i<n+1; i++){
        scanf("%lf\n", &numbers[i]);
        }
        old_average[1] = numbers[1] / 1;
    for (i=1; i<n+1; i++){
        new_average[i] = (((old_average[i] * (i)) + numbers[i+1]) / (i+1));
        old_average[i+1]=new_average[i];
        }
    printf("%lf\n", old_average[1]);
    for (i=1; i<n+1; i++){
        printf("%lf\n", new_average[i]);
    }


        //new_average[i] = (((old_average[i] * i-1) + numbers[i]) / i);
        //mean[j] = numbers[i] + mean

    //printf("%f\n", old_average[1]);
    //for (i=2; i<n+2; i++){
      //  printf("%f\n", new_average[i]);
    //}
    return 0;
}

下面是输入和输出的样子

Here is what the input and output look like

Input:  
Total amount of numbers: 10
10
8
9
15
12
2
3
8
7
11
0(this is the extra loop)
Output: 
10.0
9.0
9.0
10.5
10.8
9.3
8.4
8.4
8.2
8.5
-1.#QNAN0 (this is the extra loop)

我怎样才能解决这个问题？

How can I fix this issue?

推荐答案

删除多余的 \\ n ，意思是直到读或明年非白色 - 文件结束 - 空格字符，传递到 scanf的每个格式说明（）。

Remove extra \n, which means "read until end-of-file or next non white-space character", in each format specifier passed to scanf().

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