字符数组为int [英] Char-array to int

问题描述

我有一个数组炭输入[11] = {'0'，'2'，'7'，' - '，'1'，'1'，'2'，' 0'，'0'，'9'，'5'};

我如何将输入[0,1,2]到 INT 1 = 27 ，输入[3,4,5,6]到诠释2 = -112 输入[7,8,9,10]到 INT 3 = 95 ？

How do I convert input[0,1,2] to int one = 27, input[3,4,5,6] to int two = -112 and input[7,8,9,10] to int three = 95?

THX，JNK

推荐答案

您可以使用函数strncpy的组合（）来提取字符范围和与atoi（）将其转换为整数（或读的这个问题更多的方式将一个字符串到int转换）。

You can use a combination of strncpy() to extract the character range and atoi() to convert it to an integer (or read this question for more ways to convert a string to an int).

int extract(char *input, int from, int length) {
  char temp[length+1] = { 0 };
  strncpy(temp, input+from, length);
  return atoi(temp);
}

int main() {
  char input[11] = {'0','2','7','-','1','1','2','0','0','9','5'};
  cout << "Heading: " << extract(input, 0, 3) << endl;
  cout << "Pitch:   " << extract(input, 3, 4) << endl;
  cout << "Roll:    " << extract(input, 7, 4) << endl;
}

输出

Heading: 27
Pitch:   -112
Roll:    95

http://ideone.com/SUutl

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