为什么在getchar函数，而第一次迭代后不执行？ [英] why does getchar in while not execute after first iteration?

问题描述

我写了一个程序来通过从字符输入字符读取并打印输出，这里是我的code：

I wrote a program to read from input character by character and print it to output and here is my code:

#include <stdio.h>

main()
{

    int c;
    while((c = getchar()) != EOF)
    {
        printf("%s\n", "log1");
        printf("%c\n", c);
        printf("%s\n", "log2");
    }

}

和这是结果

a(my input)
log1
a
log2
log1


log2

但它应该有这样的结果：

but it should have this result:

a
log1
a
log2

什么是错的这个计划？

what's wrong with this program?

推荐答案

您提供输入和换行

a(my input)  You are giving a and newline

//this is because of a 
log1
a
log2 

//this is because of newline
log1


log2

检查换行，并避免打印换行符。

Check for newline and avoid printing Newline.

    while((c = getchar()) != EOF)
        {
            if(c!='\n')
               {  
                printf("%s\n", "log1");
                printf("%c\n", c);
                printf("%s\n", "log2");
               }
        }

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