用C Wordcounting程序 [英] Wordcounting program in C

问题描述

所以我尝试写统计一个文本文件中的单词数的程序。

So I am trying to write a program that counts the number of words in a text file.

main(void){
    int wordcount = 0;
    FILE *infile = fopen("Text.txt", "r");
    wordcount += word_count(infile);
    printf("%d", wordcount);
    return 0;

    }

int word_count()
{
    int wordcount(FILE *infile);
    int count;
    char it;
    while ((it  = fgets(infile)!=EOF))
    {
        if (it =='\n')
        {
            count++
        }
    }
    return count;
}

但是当我运行它，我得到了这些错误：

But when I run it, I got these errors:

infile undeclared identifier
fgets too few aruguments for function call

我在做什么错了？

what am I doing wrong?

推荐答案

首先登场，段：

int word_count()
{
    int wordcount(FILE *infile);

应该是：

int word_count(FILE *infile) {

第二，与fgets（）需要的三的参数，缓冲区地址，最大大小和文件句柄。

Secondly, fgets() takes three arguments, the buffer address, maximum size and file handle.

第三，如果与fgets（）得到的东西，它返回一个指向缓冲区，而不是一个字符。如果你想处理的字符，你应该寻找到龟etc 代替。

Third, if fgets() gets something, it returns a pointer to the buffer, not a character. If you're wanting to handle characters, you should be looking into fgetc instead.

四，检测 \\ n 字符来算的行的WOT，但话的好方法。而且你可能要检测一个最后一行没有它的换行符为另一行呢（根据您的需要）。

Fourth, detecting the \n character is a good way to count lines but wot words. And you'd probably want to detect a final line without a newline on it as another line anyway (depending on your needs).

如果你想算的话，你需要检测词和非词之间的过渡。

If you want to count words, you need to detect transitions between words and non-words.

五，你应该上移字计数功能上面主或提供它的原型上面主 。因为它是现在，它不是这样宣布你没有的类型安全。

Fifth, you should either move the word counting function to above main or provide a prototype for it above main. As it is now, it's not declared so you don't have type safety.

最后，的main（）应声明为返回一个 INT 。

And, finally, main() should be declared to return an int.

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