我怎样才能获得在C＃中每个内核的CPU负载？ [英] How can I get CPU load per core in C#?

问题描述

我怎样才能得到每个核心（四核CPU）CPU负载，在C＃中？

How can I get CPU Load per core (quadcore cpu), in C#?

感谢：）

推荐答案

您可以使用WMI或System.Diagnostics命名空间。从那里，你可以抓住任何你想要的性能计数器（但它需要一秒钟（1-1.5s）来初始化那些 - 读值是确定的，唯一的初始化速度慢）

You can either use WMI or the System.Diagnostics namespace. From there you can grab any of the performance counters you wish (however it takes a second (1-1.5s) to initialize those - reading values is ok, only initialization is slow)

code可以关注一下然后是这样的：

Code can look then like this:

    using System.Diagnostics;

    public static Double Calculate(CounterSample oldSample, CounterSample newSample)
    {
        double difference = newSample.RawValue - oldSample.RawValue;
        double timeInterval = newSample.TimeStamp100nSec - oldSample.TimeStamp100nSec;
        if (timeInterval != 0) return 100*(1 - (difference/timeInterval));
        return 0;
    }

    static void Main()
    {
        var pc = new PerformanceCounter("Processor Information", "% Processor Time");
        var cat = new PerformanceCounterCategory("Processor Information");
        var instances = cat.GetInstanceNames();
        var cs = new Dictionary<string, CounterSample>();

        foreach (var s in instances)
        { 
            pc.InstanceName = s;
            cs.Add(s, pc.NextSample());
        }

        while (true)
        {
            foreach (var s in instances)
            {
                pc.InstanceName = s;
                Console.WriteLine("{0} - {1:f}", s, Calculate(cs[s], pc.NextSample()));
                cs[s] = pc.NextSample();
            }
            System.Threading.Thread.Sleep(500);
        }
    }

重要的是，你不能依赖于本地.NET计算100nsInverse性能计数器（仅适用于0或100对我的回报...错误？），但你必须自己进行计算，并为需要最后CounterSamples的存档每个实例（实例重新present核心或这些核心的总和）。

Important thing is that you cant rely on native .net calculation for 100nsInverse performance counters (returns only 0 or 100 for me ... bug?) but you have to calculate it yourself and for that you need an archive of last CounterSamples for each instance (instances represent a core or a sum of those cores).

有似乎是这些实例的命名convetion：

There appears to be a naming convetion for those instances :

0,0 - 第一CPU核心第一
0,1 - 第一CPU第二个核心
0，_Total - 第一个CPU的总负荷
_Total - 所有CPU的总负载

0,0 - first cpu first core 0,1 - first cpu second core 0,_Total - total load of first cpu _Total - total load of all cpus

（未验证 - 不建议依赖它，直​​到进一步的调查做）......

(not verified - would not recommend to rely on it untill further investigation is done)...

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