事件从睡眠在C＃检测系统唤醒 [英] Event to detect System wake up from sleep in C#

问题描述

我需要检测系统电源状态模式。要precise，我需要它会调用当Windows 7从睡眠中唤醒的事件。我已经使用：

  SystemEvents.PowerModeChanged + = SystemEvents_PowerModeChanged;
 

但是与此事件的问题是，它被升高四次：可能当计算机进入睡眠模式和后计算机唤醒。我想这是在电脑唤醒只能引发的事件。是否有任何事件吗？

解决方案

  SystemEvents.PowerModeChanged + = OnPowerChange;私人无效OnPowerChange（对象S，PowerModeChangedEventArgs E）
{
    开关（e.Mode）
    {
        案例PowerModes.Resume：
        打破;
        案例PowerModes.Suspend：
        打破;
    }
}
 

您或许应该这样说的：
<一href=\"http://msdn.microsoft.com/en-us/library/microsoft.win32.systemevents.powermodechanged.aspx\">http://msdn.microsoft.com/en-us/library/microsoft.win32.systemevents.powermodechanged.aspx

I need to detect the system power state mode. To be precise, I need an event which fires up when windows 7 wakes up from sleep. I am already using:

SystemEvents.PowerModeChanged += SystemEvents_PowerModeChanged;

But the problem with this event is that it is raised up four times: possibly when computer goes into sleep mode and after computer wakes up. I want an event which is raised at computer wake up only. Is there any event for this?

解决方案

SystemEvents.PowerModeChanged += OnPowerChange;

private void OnPowerChange(object s, PowerModeChangedEventArgs e) 
{
    switch ( e.Mode ) 
    {
        case PowerModes.Resume: 
        break;
        case PowerModes.Suspend:
        break;
    }
}

You should probably read this: http://msdn.microsoft.com/en-us/library/microsoft.win32.systemevents.powermodechanged.aspx

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