在构造泛型类型 [英] Generic Type in constructor
问题描述
我有一个泛型类型接口,并希望对象的构造采取的通用接口
类似:
公共构造函数(INT胡说,IGenericType< T>实例)
{}
我要创建该对象指定IGenericType(控制使用反转)的代码。我还没有看到这种情况发生的方法。任何建议,以实现这一目标。
我希望有人能创建这样的对象:
构造VARNAME =新的构造函数(1,新GenericType< INT>());
您不能使构造通用的,但你可以使用一个通用的静态方法来代替:
公共静态构造函数的CreateInstance< T>(INT胡说,IGenericType< T>实例)
,然后做任何你需要的构造后,如果需要的话。 。在某些情况下,另一种方法是引入该通用接口延伸的非通用接口
编辑:由于每注释...
如果您想要保存的参数到新创建的对象,你想在一个强类型的方式做的话,那么类型必须是通用的为好。
在这一点上构造问题消失,但你的可能的希望在非泛型类型反正保留静态泛型方法:让您可以充分利用类型推断
公共静态类Foo
{
公共静态美孚< T>的CreateInstance(IGenericType< T>实例)
{
返回新的Foo< T>(实例);
}
}
公共类Foo< T>
{
公共美孚(IGenericType< T>实例)
{
//无论
}
}
..
IGenericType<串GT; X =新GenericType<串GT;();
&符LT;字符串> noInference =新的Foo<串GT;(x)的;
&符LT;字符串> withInference = Foo.CreateInstance(X);
I have a Generic Type Interface and want a constructor of an object to take in the Generic Interface.
Like:
public Constructor(int blah, IGenericType<T> instance)
{}
I want the code that creates this object to specify the IGenericType (use Inversion of Control). I have not seen a way for this to happen. Any suggestions to accomplish this?
I want someone to create the object like:
Constructor varname = new Constructor(1, new GenericType<int>());
You can't make constructors generic, but you can use a generic static method instead:
public static Constructor CreateInstance<T>(int blah, IGenericType<T> instance)
and then do whatever you need to after the constructor, if required. Another alternative in some cases might be to introduce a non-generic interface which the generic interface extends.
EDIT: As per the comments...
If you want to save the argument into the newly created object, and you want to do so in a strongly typed way, then the type must be generic as well.
At that point the constructor problem goes away, but you may want to keep a static generic method anyway in a non-generic type: so you can take advantage of type inference:
public static class Foo
{
public static Foo<T> CreateInstance(IGenericType<T> instance)
{
return new Foo<T>(instance);
}
}
public class Foo<T>
{
public Foo(IGenericType<T> instance)
{
// Whatever
}
}
...
IGenericType<string> x = new GenericType<string>();
Foo<string> noInference = new Foo<string>(x);
Foo<string> withInference = Foo.CreateInstance(x);
这篇关于在构造泛型类型的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!