IP地址递增问题 [英] ip address increment problem

问题描述

我想提高我的IP地址和;

I want to increase my ip address and;

下面是代码

 ipAddressControl1.Text = "192.168.1.255";

 byte[] ip = ipAddressControl1.GetAddressBytes();
 ip[3] = (byte)(++ip[3]);

 IPAddress ipAddress1 = new IPAddress(ip);
 MessageBox.Show(ipAddress1.ToString());

或我也试过这种

ipAddressControl3.Text = "192.168.1.255";
 IPAddress ipAddress1 = new IPAddress(ıpAddressControl3.GetAddressBytes());
 ipAddress1.Address += 0x1 << 24;
 MessageBox.Show(ipAddress1.ToString());

但他们两人给我192.168.1.0，但我希望得到的值作为192.168.2.0

but both of them gives me 192.168.1.0 but I want to get value as 192.168.2.0

推荐答案

您的问题是，你不增加 IP [2] 时 IP [3] 环绕（依此类推，直至层次结构）。下面的代码应该做的伎俩，终于从 255.255.255.255 包装到 0.0.0.0 ：

Your problem is that you're not increasing ip[2] when ip[3] wraps around (and so on up the hierarchy). The following code should do the trick, finally wrapping from 255.255.255.255 to 0.0.0.0:

byte[] ip = ipAddressControl1.GetAddressBytes();
ip[3] = (byte)(ip[3] + 1);
if (ip[3] == 0) {
    ip[2] = (byte)(ip[2] + 1);
    if (ip[2] == 0) {
        ip[1] = (byte)(ip[1] + 1);
        if (ip[1] == 0) {
            ip[0] = (byte)(ip[0] + 1);
        }
    }
}

以下也可工作：

The following may also work:

byte[] ip = ipAddressControl1.GetAddressBytes();
if (++ip[3] == 0)
    if (++ip[2] == 0)
        if (++ip[1] == 0)
            ++ip[0];

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