阅读和使用C＃，C ++或Python的Gmail电子邮件解析 [英] Reading and parsing email from Gmail using C#, C++ or Python

问题描述

我必须做一个Windows应用程序，从次次访问Gmail帐户，并检查是否有新邮件。但如果是，它必须读取电子邮件正文和主题（一个简单的文本电子邮件，没有图像或附件）。

I have to do a Windows application that from times to times access a Gmail account and checks if there is a new email. In case there is, it must read the email body and subject (a simple text email, without images or attachments).

请，不使用支付库，并在使用的任何其他库的情况下，给出下载路径。

Please, do not use paid libs, and in case of any other libs used, give the download path.

和我需要的电子邮件正文只规定。所以，如果来自Gmail的长期和复杂的消息能够被解析只有两个包含主题和身体的字符串，这将是完美的。

And I need the email body and subject only. So if the long and complex message that comes from Gmail could be parsed and only two strings containing the subject and the body, it would be perfect.

最后，我只有获得自上次执行到达的新邮件。这样读出的消息可以被标记为读，只有新的（标记为新的）被认为是

Finally, I only have to get the new messages arrived since the last execution. So the read messages could be marked as "read" and only the new ones (marked as "new") are considered.

的代码可以被写入在Python或C ++ ，但我更喜欢它在C＃

The code can be written in Python or C++, but I prefer it in C#.

相关问题：

• 为Python IMAP电子邮件访问正确格式化的例子吗？

• Properly formatted example for Python iMAP email access?

推荐答案

此打印看不见的邮件的主题和正文，并且看到标志的消息。

This prints the subject and body of unseen messages, and marks those messages as seen.

import imaplib
import email

def extract_body(payload):
    if isinstance(payload,str):
        return payload
    else:
        return '\n'.join([extract_body(part.get_payload()) for part in payload])

conn = imaplib.IMAP4_SSL("imap.gmail.com", 993)
conn.login("user", "password")
conn.select()
typ, data = conn.search(None, 'UNSEEN')
try:
    for num in data[0].split():
        typ, msg_data = conn.fetch(num, '(RFC822)')
        for response_part in msg_data:
            if isinstance(response_part, tuple):
                msg = email.message_from_string(response_part[1])
                subject=msg['subject']                   
                print(subject)
                payload=msg.get_payload()
                body=extract_body(payload)
                print(body)
        typ, response = conn.store(num, '+FLAGS', r'(\Seen)')
finally:
    try:
        conn.close()
    except:
        pass
    conn.logout()

许多代码以上来自道格乐门教程imaplib 。

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