正则表达式来匹配的东西，不是一个具体的子 [英] Regex to match against something that is not a specific substring

问题描述

我要寻找一个正则表达式，将匹配一个字符串开始，不具有一定的子结束串

I am looking for a regex that will match a string that starts with one substring and does not end with a certain substring.

例如：

// Updated to be correct, thanks @Apocalisp
^foo.*(?<!bar)$

应该匹配任何以foo的开始，不与酒吧结尾。我了解[^ ...]语法，但我无法找到任何东西，会做一个字符串，而不是单个字符。

Should match anything that starts with "foo" and doesn't end with "bar". I know about the [^...] syntax, but I can't find anything that will do that for a string instead of single characters.

我特别想对Java的正则表达式做到这一点，但我碰到的这个答案，这样对其他的正则表达式引擎之前，将是巨大的。

I am specifically trying to do this for Java's regex, but I've run into this before so answers for other regex engines would be great too.

感谢@Kibbee验证这个工作在C＃以及。

Thanks to @Kibbee for verifying that this works in C# as well.

推荐答案

我想你想这种情况下的负后向，就像这样：

I think in this case you want negative lookbehind, like so:

foo.*(?<!bar)

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