正则表达式匹配代码中的具体注释 [英] Regex to match specific comments in code

问题描述

有没有正规的专家谁可以帮助我清理以下源代码？我将通过一些现有的代码，我看到类似于以下几个实例：

  public enum Numbers 
 { 
 ///< summary> 
 /// One = 1，
 ///< / summary> 
 One = 1，
 
 ///< summary> 
 /// Two = 2，
 ///< / summary> 
 Two = 2，
 
 ///< summary> 
 /// Three = 3，
 ///< / summary> 
 Three = 3，
 
 ///< summary> 
 /// Four = 4但不要使用它，因为它会破坏一切，
 ///< / summary> 
 Four = 4，
} 
  

除非有人能告诉我对于1-3是必要的，我想做一个find / replace（删除）所有的注释，不添加任何值的代码。从浏览代码，我认为可以放心，假设任何类似于/// word = number的行都可以替换。清理，我认为它应该看起来像：

  public enum数字
 {
 One = 1， 
 Two = 2，
 Three = 3，
 
 ///< summary> 
 /// Four = 4但不要使用它，因为它会破坏一切，
 ///< / summary> 
 Four = 4，
} 
  

通过帮助我，你真的在​​帮助自己。因为谁知道，有一天你可能会维护这个代码！

解决方案

使用VS2008 FindAndReplace我试过这个工作; >

查找内容：

  \\< summary\>。* \\\
。* \ =：b：d [：b，] * \\\
。* \< \ / summary \> \\\
 
  

替换为：

 （空）
  

strong>

正则表达式

Are there any regex experts who can help me clean up the following source code? I'm going through some existing code and I see several instances similar to the following:

public enum Numbers
{
    /// <summary>
    /// One = 1, 
    /// </summary>
    One = 1,

    /// <summary>
    /// Two = 2, 
    /// </summary>
    Two = 2,

    /// <summary>
    /// Three = 3, 
    /// </summary>
    Three = 3,

    /// <summary>
    /// Four = 4 but don't use this because it will break everything, 
    /// </summary>
    Four = 4,
}

Unless someone can tell me that the comments for 1-3 are necessary, I'd like to do a find/replace (remove) on all of the comments that don't add any value to the code. From browsing the code I think it's safe to assume that any line that resembles "/// word = number," can be replaced. Cleaned up, I think it should look like:

public enum Numbers
{
    One = 1,
    Two = 2,
    Three = 3,

    /// <summary>
    /// Four = 4 but don't use this because it will break everything, 
    /// </summary>
    Four = 4,
}

Your help is greatly appreciated! And by helping me, you are really helping yourself. Because who knows, someday you might be maintaining this very code!

解决方案

With VS2008 FindAndReplace I tried this and worked;

Find what:

/// \<summary\>.*\n.*\=:b:d[:b,]*\n.*\<\/summary\>\n

Replace with:

(empty)

Use:

Regular expressions

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