如何嘲笑一个方法调用，需要一个动态对象 [英] How to mock a method call that takes a dynamic object

问题描述

说我有以下几点：

public interface ISession 
{
   T Get<T>(dynamic filter); }
}

和我有下面的代码，我想测试：

And I have the following code that I want to test:

var user1 = session.Get<User>(new {Name = "test 1"});
var user2 = session.Get<User>(new {Name = "test 2"});

我怎么会嘲笑这个电话？

How would I mock this call?

使用起订量，我厌倦了这样做的：

Using Moq, I tired doing this:

var sessionMock = new Mock<ISession>();
sessionMock.Setup(x => x.Get<User>(new {Name = "test 1")).Returns(new User{Id = 1});
sessionMock.Setup(x => x.Get<User>(new {Name = "test 1")).Returns(new User{Id = 2});

和没有工作。返回的结果为空

And that didn't work. The returned results is null

我也试着做犀牛制品以下内容：

I also tried to do the following with Rhino Mocks:

var session = MockRepository.GenerateStub<ISession>();
session.Stub(x => x.Get<User>(new {Name = "test 1"})).Return(new User{Id=1});

没有任何运气。空试。

所以，我会怎么做呢？

谢谢，

推荐答案

在解决方案是使用 It.Is<对象> 与反思一起匹配器。你不能使用表达式目录树动态的，所以 It.Is<动态> 将无法正常工作，这就是为什么你需要思考度日名称的属性值：

On solution is to use the It.Is<object> matcher together with reflection. You cannot use dynamic in expression trees so It.Is<dynamic> won't work that's why you need reflection to get the your property value by name:

sessionMock
    .Setup(x => x.Get<User>(
        It.Is<object>(d => d.GetPropertyValue<string>("Name") == "test 1")))
    .Returns(new User{Id = 1});
sessionMock
    .Setup(x => x.Get<User>(
        It.Is<object>(d => d.GetPropertyValue<string>("Name") == "test 2")))
    .Returns(new User { Id = 2 });

其中， GetPropertyValue 是一个小帮手：

public static class ReflectionExtensions
{
    public static T GetPropertyValue<T>(this object obj, string propertyName)
    {
        return (T) obj.GetType().GetProperty(propertyName).GetValue(obj, null);
    }
}

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