二进制和运营 [英] Binary AND Operations

问题描述

我试图根据MSDN文章有关的&安培;操作

I'm trying to do some Binary AND operations in c# based on MSDN article about & Operator

如果我做的：

1111 & 10 = 2 (0010) // Which is what i expect

然而，

However,

1111 & 100 = 68 (1000100) // Which is **not** what i expect.

我还以为输出本来的 100 的

我想什么？

推荐答案

您所指定的数字，1111和100，都被视为基地10个号码，而不是二进制数。

The numbers you specified, 1111 and 100, are being treated as base 10 numbers, not binary numbers.

如果您希望二进制整数1111你应该输入 15 ，因为这是该基地10版本。所以：

If you want the binary integer 1111 you should enter 15, as that's the base 10 version. So:

15安培; 4 将成为 4 ，符合市场预期。

15 & 4 will become 4, as expected.

有是在C＃中没有语法在指定二进制文字整数。你没有任何选择，但他们自己转换为基地十，或使用运行时转换如通过 Convert.ToInt 。

There is no syntax in C# for specifying an integer literal in binary. You don't have any choice but to convert them into base ten yourself, or use a runtime-conversion such as through Convert.ToInt.

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