我如何扭转我的音量数学对我的音量滑块？ [英] How do I reverse my sound volume math for my volume slider?

问题描述

我要建一个视频播放器和我还挺停留在音量滑块部分。这是一个YouTube式的垂直滑块，这意味着如果滑块是在顶部位置量应该是100％，如果将滑块拖动到下方位置的声音应该是0。目前，它在做什么，我想要的正好相反：（

I'm building a video player and am kinda stuck at the volume slider part. It's a YouTube style vertical slider, meaning if the slider is in the top position volume should be 100% and if the slider is dragged to the bottom position sound should be 0. Currently it's doing the opposite of what I want :(

拖动滑块降低将会使声音变得更大，而向上拖动会降低它。

Dragging the slider down will make the sound louder, while dragging up lowers it.

下面是低于处理音量滑块我的code。

Here is my code below dealing with the volume slider.

// Sound Controller Settings ······························
   soundController = new SoundController();
   soundContrColor = soundController.colorChip;
   soundContrGray  = soundController.grayCover;
   soundContrGray.visible     = false;
   soundController.visible    = true;
   soundController.buttonMode = true;
   soundController.soundSlider.addEventListener(MouseEvent.MOUSE_DOWN, sliderDown);

// SoundController Button Mouse Events ························
   public function sliderDown(event:MouseEvent):void
   {
       soundController.soundSlider.startDrag(false, dragBounds);
       soundController.soundSlider.addEventListener(MouseEvent.MOUSE_MOVE, sliderMove);
       soundController.soundSlider.addEventListener(MouseEvent.MOUSE_UP, sliderUp);
       soundContrGray.visible = true;
   }

   public function sliderMove(event:MouseEvent):void
       {
       soundContrGray.height = soundController.soundSlider.y;
       userVolume = Math.round(((soundContrGray.y * soundContrGray.height) / 10) - 4);
       //userVolume = soundContrGray.height;
       setVolume(userVolume);

       trace("soundController.mouseY = "+soundController.soundSlider.y);
       trace("soundContrColor.height = "+Math.round(soundContrGray.height));
       trace("userVolume             = "+userVolume+"\r");

       event.updateAfterEvent();
       }

    public function sliderUp(event:MouseEvent):void
    {
        lastVolPoint = soundContrGray.height;
        setVolume(userVolume);
        event.updateAfterEvent();

        soundController.soundSlider.stopDrag();
        soundController.soundSlider.removeEventListener(MouseEvent.MOUSE_MOVE, sliderMove);
        soundController.soundSlider.removeEventListener(MouseEvent.MOUSE_UP, sliderUp);
    }

[微量]当我一路拖到顶部：

[TRACES] when I drag all the way to the top:

soundController.mouseY = 6
soundContrGray.height  = 6
userVolume             = 0

[微量]当我拖累一路走低：

[TRACES] when I drag all the way down:

soundController.mouseY = 56
soundContrGray.height  = 56
userVolume             = 30

我相信这是问题所在：

I believe this is where the problem lies:

userVolume = Math.round(((soundContrGray.y * soundContrGray.height) / 10) - 4);

在（ - 4）。是一个偏移值，所以当你拖动它都将其关闭的方式，它的0，而不是4 的
我需要以某种方式扭转这一点，所以在上面的痕迹会掉...下去会使userVolume = 4和上升将使其30。

The (-4) is an offset value so when you drag it all the way to turn it off, it's 0 and not 4.
I need to reverse this somehow, so the traces above will swap... going down will make userVolume = 4 and going up will make it 30.

在此先感谢任何人，需要看看这个！ ：）

Thanks in advance for anyone that takes a look at this one! :)

推荐答案

我一定是失去了一些东西，因为它不能被这个简单的，可以吗？

I must be missing something because it can't be this simple, can it?

userVolume = 30-Math.round(((soundContrGray.y * soundContrGray.height) / 10) - 4);

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